Integrand size = 24, antiderivative size = 183 \[ \int \frac {\left (a+b x^2\right )^2}{x^6 \left (c+d x^2\right )^{5/2}} \, dx=-\frac {a^2}{5 c x^5 \left (c+d x^2\right )^{3/2}}-\frac {2 a (5 b c-4 a d)}{15 c^2 x^3 \left (c+d x^2\right )^{3/2}}-\frac {5 b^2 c^2-4 a d (5 b c-4 a d)}{5 c^3 x \left (c+d x^2\right )^{3/2}}-\frac {4 d \left (5 b^2 c^2-4 a d (5 b c-4 a d)\right ) x}{15 c^4 \left (c+d x^2\right )^{3/2}}-\frac {8 d \left (5 b^2 c^2-4 a d (5 b c-4 a d)\right ) x}{15 c^5 \sqrt {c+d x^2}} \]
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Time = 0.11 (sec) , antiderivative size = 183, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.208, Rules used = {473, 464, 277, 198, 197} \[ \int \frac {\left (a+b x^2\right )^2}{x^6 \left (c+d x^2\right )^{5/2}} \, dx=-\frac {a^2}{5 c x^5 \left (c+d x^2\right )^{3/2}}-\frac {5 b^2-\frac {4 a d (5 b c-4 a d)}{c^2}}{5 c x \left (c+d x^2\right )^{3/2}}-\frac {8 d x \left (5 b^2 c^2-4 a d (5 b c-4 a d)\right )}{15 c^5 \sqrt {c+d x^2}}-\frac {4 d x \left (5 b^2 c^2-4 a d (5 b c-4 a d)\right )}{15 c^4 \left (c+d x^2\right )^{3/2}}-\frac {2 a (5 b c-4 a d)}{15 c^2 x^3 \left (c+d x^2\right )^{3/2}} \]
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Rule 197
Rule 198
Rule 277
Rule 464
Rule 473
Rubi steps \begin{align*} \text {integral}& = -\frac {a^2}{5 c x^5 \left (c+d x^2\right )^{3/2}}+\frac {\int \frac {2 a (5 b c-4 a d)+5 b^2 c x^2}{x^4 \left (c+d x^2\right )^{5/2}} \, dx}{5 c} \\ & = -\frac {a^2}{5 c x^5 \left (c+d x^2\right )^{3/2}}-\frac {2 a (5 b c-4 a d)}{15 c^2 x^3 \left (c+d x^2\right )^{3/2}}-\frac {1}{5} \left (-5 b^2+\frac {4 a d (5 b c-4 a d)}{c^2}\right ) \int \frac {1}{x^2 \left (c+d x^2\right )^{5/2}} \, dx \\ & = -\frac {a^2}{5 c x^5 \left (c+d x^2\right )^{3/2}}-\frac {2 a (5 b c-4 a d)}{15 c^2 x^3 \left (c+d x^2\right )^{3/2}}-\frac {5 b^2-\frac {4 a d (5 b c-4 a d)}{c^2}}{5 c x \left (c+d x^2\right )^{3/2}}-\frac {\left (4 d \left (5 b^2-\frac {4 a d (5 b c-4 a d)}{c^2}\right )\right ) \int \frac {1}{\left (c+d x^2\right )^{5/2}} \, dx}{5 c} \\ & = -\frac {a^2}{5 c x^5 \left (c+d x^2\right )^{3/2}}-\frac {2 a (5 b c-4 a d)}{15 c^2 x^3 \left (c+d x^2\right )^{3/2}}-\frac {5 b^2-\frac {4 a d (5 b c-4 a d)}{c^2}}{5 c x \left (c+d x^2\right )^{3/2}}-\frac {4 d \left (5 b^2-\frac {4 a d (5 b c-4 a d)}{c^2}\right ) x}{15 c^2 \left (c+d x^2\right )^{3/2}}-\frac {\left (8 d \left (5 b^2-\frac {4 a d (5 b c-4 a d)}{c^2}\right )\right ) \int \frac {1}{\left (c+d x^2\right )^{3/2}} \, dx}{15 c^2} \\ & = -\frac {a^2}{5 c x^5 \left (c+d x^2\right )^{3/2}}-\frac {2 a (5 b c-4 a d)}{15 c^2 x^3 \left (c+d x^2\right )^{3/2}}-\frac {5 b^2-\frac {4 a d (5 b c-4 a d)}{c^2}}{5 c x \left (c+d x^2\right )^{3/2}}-\frac {4 d \left (5 b^2-\frac {4 a d (5 b c-4 a d)}{c^2}\right ) x}{15 c^2 \left (c+d x^2\right )^{3/2}}-\frac {8 d \left (5 b^2-\frac {4 a d (5 b c-4 a d)}{c^2}\right ) x}{15 c^3 \sqrt {c+d x^2}} \\ \end{align*}
Time = 0.21 (sec) , antiderivative size = 142, normalized size of antiderivative = 0.78 \[ \int \frac {\left (a+b x^2\right )^2}{x^6 \left (c+d x^2\right )^{5/2}} \, dx=\frac {-5 b^2 c^2 x^4 \left (3 c^2+12 c d x^2+8 d^2 x^4\right )+10 a b c x^2 \left (-c^3+6 c^2 d x^2+24 c d^2 x^4+16 d^3 x^6\right )-a^2 \left (3 c^4-8 c^3 d x^2+48 c^2 d^2 x^4+192 c d^3 x^6+128 d^4 x^8\right )}{15 c^5 x^5 \left (c+d x^2\right )^{3/2}} \]
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Time = 2.98 (sec) , antiderivative size = 131, normalized size of antiderivative = 0.72
method | result | size |
pseudoelliptic | \(\frac {\left (-15 b^{2} x^{4}-10 a b \,x^{2}-3 a^{2}\right ) c^{4}+8 x^{2} d \left (-\frac {15}{2} b^{2} x^{4}+\frac {15}{2} a b \,x^{2}+a^{2}\right ) c^{3}-48 x^{4} d^{2} \left (\frac {5}{6} b^{2} x^{4}-5 a b \,x^{2}+a^{2}\right ) c^{2}-192 x^{6} d^{3} \left (-\frac {5 b \,x^{2}}{6}+a \right ) a c -128 a^{2} d^{4} x^{8}}{15 \left (d \,x^{2}+c \right )^{\frac {3}{2}} x^{5} c^{5}}\) | \(131\) |
risch | \(-\frac {\sqrt {d \,x^{2}+c}\, \left (73 a^{2} d^{2} x^{4}-80 x^{4} a b c d +15 b^{2} c^{2} x^{4}-14 a^{2} c d \,x^{2}+10 a b \,c^{2} x^{2}+3 a^{2} c^{2}\right )}{15 c^{5} x^{5}}-\frac {d \left (a d -b c \right ) \left (11 a \,d^{2} x^{2}-5 b c d \,x^{2}+12 a c d -6 b \,c^{2}\right ) x \sqrt {d \,x^{2}+c}}{3 \left (d^{2} x^{4}+2 c d \,x^{2}+c^{2}\right ) c^{5}}\) | \(152\) |
gosper | \(-\frac {128 a^{2} d^{4} x^{8}-160 a b c \,d^{3} x^{8}+40 b^{2} c^{2} d^{2} x^{8}+192 a^{2} c \,d^{3} x^{6}-240 a b \,c^{2} d^{2} x^{6}+60 b^{2} c^{3} d \,x^{6}+48 a^{2} c^{2} d^{2} x^{4}-60 a b \,c^{3} d \,x^{4}+15 b^{2} c^{4} x^{4}-8 a^{2} c^{3} d \,x^{2}+10 a b \,c^{4} x^{2}+3 a^{2} c^{4}}{15 x^{5} \left (d \,x^{2}+c \right )^{\frac {3}{2}} c^{5}}\) | \(158\) |
trager | \(-\frac {128 a^{2} d^{4} x^{8}-160 a b c \,d^{3} x^{8}+40 b^{2} c^{2} d^{2} x^{8}+192 a^{2} c \,d^{3} x^{6}-240 a b \,c^{2} d^{2} x^{6}+60 b^{2} c^{3} d \,x^{6}+48 a^{2} c^{2} d^{2} x^{4}-60 a b \,c^{3} d \,x^{4}+15 b^{2} c^{4} x^{4}-8 a^{2} c^{3} d \,x^{2}+10 a b \,c^{4} x^{2}+3 a^{2} c^{4}}{15 x^{5} \left (d \,x^{2}+c \right )^{\frac {3}{2}} c^{5}}\) | \(158\) |
default | \(b^{2} \left (-\frac {1}{c x \left (d \,x^{2}+c \right )^{\frac {3}{2}}}-\frac {4 d \left (\frac {x}{3 c \left (d \,x^{2}+c \right )^{\frac {3}{2}}}+\frac {2 x}{3 c^{2} \sqrt {d \,x^{2}+c}}\right )}{c}\right )+a^{2} \left (-\frac {1}{5 c \,x^{5} \left (d \,x^{2}+c \right )^{\frac {3}{2}}}-\frac {8 d \left (-\frac {1}{3 c \,x^{3} \left (d \,x^{2}+c \right )^{\frac {3}{2}}}-\frac {2 d \left (-\frac {1}{c x \left (d \,x^{2}+c \right )^{\frac {3}{2}}}-\frac {4 d \left (\frac {x}{3 c \left (d \,x^{2}+c \right )^{\frac {3}{2}}}+\frac {2 x}{3 c^{2} \sqrt {d \,x^{2}+c}}\right )}{c}\right )}{c}\right )}{5 c}\right )+2 a b \left (-\frac {1}{3 c \,x^{3} \left (d \,x^{2}+c \right )^{\frac {3}{2}}}-\frac {2 d \left (-\frac {1}{c x \left (d \,x^{2}+c \right )^{\frac {3}{2}}}-\frac {4 d \left (\frac {x}{3 c \left (d \,x^{2}+c \right )^{\frac {3}{2}}}+\frac {2 x}{3 c^{2} \sqrt {d \,x^{2}+c}}\right )}{c}\right )}{c}\right )\) | \(251\) |
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Time = 0.29 (sec) , antiderivative size = 171, normalized size of antiderivative = 0.93 \[ \int \frac {\left (a+b x^2\right )^2}{x^6 \left (c+d x^2\right )^{5/2}} \, dx=-\frac {{\left (8 \, {\left (5 \, b^{2} c^{2} d^{2} - 20 \, a b c d^{3} + 16 \, a^{2} d^{4}\right )} x^{8} + 12 \, {\left (5 \, b^{2} c^{3} d - 20 \, a b c^{2} d^{2} + 16 \, a^{2} c d^{3}\right )} x^{6} + 3 \, a^{2} c^{4} + 3 \, {\left (5 \, b^{2} c^{4} - 20 \, a b c^{3} d + 16 \, a^{2} c^{2} d^{2}\right )} x^{4} + 2 \, {\left (5 \, a b c^{4} - 4 \, a^{2} c^{3} d\right )} x^{2}\right )} \sqrt {d x^{2} + c}}{15 \, {\left (c^{5} d^{2} x^{9} + 2 \, c^{6} d x^{7} + c^{7} x^{5}\right )}} \]
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\[ \int \frac {\left (a+b x^2\right )^2}{x^6 \left (c+d x^2\right )^{5/2}} \, dx=\int \frac {\left (a + b x^{2}\right )^{2}}{x^{6} \left (c + d x^{2}\right )^{\frac {5}{2}}}\, dx \]
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Time = 0.20 (sec) , antiderivative size = 244, normalized size of antiderivative = 1.33 \[ \int \frac {\left (a+b x^2\right )^2}{x^6 \left (c+d x^2\right )^{5/2}} \, dx=-\frac {8 \, b^{2} d x}{3 \, \sqrt {d x^{2} + c} c^{3}} - \frac {4 \, b^{2} d x}{3 \, {\left (d x^{2} + c\right )}^{\frac {3}{2}} c^{2}} + \frac {32 \, a b d^{2} x}{3 \, \sqrt {d x^{2} + c} c^{4}} + \frac {16 \, a b d^{2} x}{3 \, {\left (d x^{2} + c\right )}^{\frac {3}{2}} c^{3}} - \frac {128 \, a^{2} d^{3} x}{15 \, \sqrt {d x^{2} + c} c^{5}} - \frac {64 \, a^{2} d^{3} x}{15 \, {\left (d x^{2} + c\right )}^{\frac {3}{2}} c^{4}} - \frac {b^{2}}{{\left (d x^{2} + c\right )}^{\frac {3}{2}} c x} + \frac {4 \, a b d}{{\left (d x^{2} + c\right )}^{\frac {3}{2}} c^{2} x} - \frac {16 \, a^{2} d^{2}}{5 \, {\left (d x^{2} + c\right )}^{\frac {3}{2}} c^{3} x} - \frac {2 \, a b}{3 \, {\left (d x^{2} + c\right )}^{\frac {3}{2}} c x^{3}} + \frac {8 \, a^{2} d}{15 \, {\left (d x^{2} + c\right )}^{\frac {3}{2}} c^{2} x^{3}} - \frac {a^{2}}{5 \, {\left (d x^{2} + c\right )}^{\frac {3}{2}} c x^{5}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 509 vs. \(2 (163) = 326\).
Time = 0.31 (sec) , antiderivative size = 509, normalized size of antiderivative = 2.78 \[ \int \frac {\left (a+b x^2\right )^2}{x^6 \left (c+d x^2\right )^{5/2}} \, dx=-\frac {x {\left (\frac {{\left (5 \, b^{2} c^{6} d^{3} - 16 \, a b c^{5} d^{4} + 11 \, a^{2} c^{4} d^{5}\right )} x^{2}}{c^{9} d} + \frac {6 \, {\left (b^{2} c^{7} d^{2} - 3 \, a b c^{6} d^{3} + 2 \, a^{2} c^{5} d^{4}\right )}}{c^{9} d}\right )}}{3 \, {\left (d x^{2} + c\right )}^{\frac {3}{2}}} + \frac {2 \, {\left (15 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{8} b^{2} c^{2} \sqrt {d} - 60 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{8} a b c d^{\frac {3}{2}} + 45 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{8} a^{2} d^{\frac {5}{2}} - 60 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{6} b^{2} c^{3} \sqrt {d} + 300 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{6} a b c^{2} d^{\frac {3}{2}} - 240 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{6} a^{2} c d^{\frac {5}{2}} + 90 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{4} b^{2} c^{4} \sqrt {d} - 500 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{4} a b c^{3} d^{\frac {3}{2}} + 490 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{4} a^{2} c^{2} d^{\frac {5}{2}} - 60 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{2} b^{2} c^{5} \sqrt {d} + 340 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{2} a b c^{4} d^{\frac {3}{2}} - 320 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{2} a^{2} c^{3} d^{\frac {5}{2}} + 15 \, b^{2} c^{6} \sqrt {d} - 80 \, a b c^{5} d^{\frac {3}{2}} + 73 \, a^{2} c^{4} d^{\frac {5}{2}}\right )}}{15 \, {\left ({\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{2} - c\right )}^{5} c^{4}} \]
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Time = 5.88 (sec) , antiderivative size = 298, normalized size of antiderivative = 1.63 \[ \int \frac {\left (a+b x^2\right )^2}{x^6 \left (c+d x^2\right )^{5/2}} \, dx=\frac {2\,a\,\sqrt {d\,x^2+c}\,\left (7\,a\,d-5\,b\,c\right )}{15\,c^4\,x^3}-\frac {\frac {73\,a^2\,c^2\,d^2-80\,a\,b\,c^3\,d+15\,b^2\,c^4}{30\,c^5}-\frac {c\,\left (\frac {d\,\left (73\,a^2\,c^2\,d^2-80\,a\,b\,c^3\,d+15\,b^2\,c^4\right )}{18\,c^6}+\frac {c\,\left (\frac {4\,a\,d^3\,\left (7\,a\,d-5\,b\,c\right )}{45\,c^5}-\frac {a\,d^3\,\left (43\,a\,d-35\,b\,c\right )}{9\,c^5}\right )}{d}+\frac {a\,d^2\,\left (43\,a\,d-35\,b\,c\right )}{15\,c^4}\right )}{d}}{x\,{\left (d\,x^2+c\right )}^{3/2}}-\frac {a^2\,\sqrt {d\,x^2+c}}{5\,c^3\,x^5}-\frac {x^2\,\left (\frac {2\,d\,\left (78\,a^2\,c\,d^2-90\,a\,b\,c^2\,d+20\,b^2\,c^3\right )}{15\,c^6}-\frac {4\,a\,d^2\,\left (7\,a\,d-5\,b\,c\right )}{15\,c^5}\right )+\frac {78\,a^2\,c\,d^2-90\,a\,b\,c^2\,d+20\,b^2\,c^3}{15\,c^5}}{x\,\sqrt {d\,x^2+c}} \]
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